5(2x^2-3)=4(x^2-10)

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Solution for 5(2x^2-3)=4(x^2-10) equation:


Simplifying
5(2x2 + -3) = 4(x2 + -10)

Reorder the terms:
5(-3 + 2x2) = 4(x2 + -10)
(-3 * 5 + 2x2 * 5) = 4(x2 + -10)
(-15 + 10x2) = 4(x2 + -10)

Reorder the terms:
-15 + 10x2 = 4(-10 + x2)
-15 + 10x2 = (-10 * 4 + x2 * 4)
-15 + 10x2 = (-40 + 4x2)

Solving
-15 + 10x2 = -40 + 4x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x2' to each side of the equation.
-15 + 10x2 + -4x2 = -40 + 4x2 + -4x2

Combine like terms: 10x2 + -4x2 = 6x2
-15 + 6x2 = -40 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-15 + 6x2 = -40 + 0
-15 + 6x2 = -40

Add '15' to each side of the equation.
-15 + 15 + 6x2 = -40 + 15

Combine like terms: -15 + 15 = 0
0 + 6x2 = -40 + 15
6x2 = -40 + 15

Combine like terms: -40 + 15 = -25
6x2 = -25

Divide each side by '6'.
x2 = -4.166666667

Simplifying
x2 = -4.166666667

Reorder the terms:
4.166666667 + x2 = -4.166666667 + 4.166666667

Combine like terms: -4.166666667 + 4.166666667 = 0.000000000
4.166666667 + x2 = 0.000000000

The solution to this equation could not be determined.

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